A transistor can be used as an analogue device or a DIGITAL device.
It has been covered as an analogue device in audio amplifiers all over the web and
in text books. But its main use in recent times has been as a digital
device.
In other words we are talking about its use in DIGITAL CIRCUITS where it
is either ON or OFF and is consuming little or no current.
This mode of operation has taken over electronics designs because the
two states have fixed and rigid values. There is no "half-on" or
"one quarter off."
And because it is either ON or OFF, the condition is 100% reliable,
predictable and copyable.
When we talk about this mode of operation, we also find there is a better
component than the ordinary transistor. It is called the Field Effect
Transistor (FET) because it has a characteristic of having a very small
voltage across it when a large current flows. A common transistor has a
voltage of about 0.3v to 0.8v or more across the collector-emitter terminals and even though
this voltage is very small, when a high current flows, the transistor
will get very hot.
If we replace it with a FET, the device stays cool or even cold. The
voltage across it will be only a few millivolts to a few hundred
millivolts.
This is a great advantage as no heat-fin may be needed.
But it is important to drive both devices with a what we say is a high
amplitude signal. This is especially needed for a FET as the gate needs
a few volts for it to operate and a slightly higher voltage to make sure
it is turned ON.
An ordinary transistor needs just 0.7v.
When we have a high amplitude signal, a digital-design can be easily converted to a FET design.
All you have to know is the base of an ordinary transistor is now the gate
of a FET and the input voltage
needs to be more than about 2.5v.
I say "about" because the family of FETs has a wide range of gate
voltages and you need to refer to a specification-sheet for the exact
value.
Here is the circuit for a common-emitter stage and a common-source
stage:

The common transistor and FET
transistor
Provided the common
transistor has a base resistor to prevent the base being pulled higher
than 0.7v, either device will work in the project you are designing.

The normal transistor MUST have a
base resistor
In a Digital Stage, the input waveform can be any amplitude and any
shape - with exceptions, as mentioned below.
If an ordinary transistor (commonly called a Bi-Polar Junction
Transistor - BJT) is used, the
transistor will turn ON fully when the signal is above 0.7v and turn OFF
when the signal is below 0.4v. A resistor on the input line is
needed to "match up" the signal and prevent the input of the transistor
being damaged as the base must not be forced to rise above 0.7v.
If a FET is used, it will turn ON when the signal is above about 1v but the
signal must be more than 2.5v to 4v to turn ON fully. The gate can
be supplied with a signal as high as 18v but the additional voltage is
not needed.
That's the only differences and similarities.
The input signal can be a square-wave, sine-wave, triangle wave, pulse
or noise and the transistor or FET will only respond when the signal is
above or below the values mentioned above.
However the rise and fall of the signal must be as fast as possible to
prevent the device getting hot.
The device is basically in a "resting" or turned-OFF state and the
signal turns it ON.
In other words the device is not "self-biased" or "pre-biased" or
partially turned ON in any way.
For a transistor, the signal needs to be able to supply a small current
as the transistor is current-driven device.
For a FET, this current is microscopic as it is voltage-driven.
This type of stage is called a DIGITAL STAGE.
It has a number of advantages.
By turning the stage ON and OFF very quickly, a LOAD such as a motor or
solenoid or
LED can be activated.
If the ON-time is reduced, the motor slows down and the LED dims. During
this cycling the transistor stays completely cold.
This is called PULSE WIDTH MODULATION or FREQUENCY MODULATION and is the basis of an electric car accelerating and flashing LED
road-signs.
The ON-time and OFF-time is called the mark-space ratio and this is
controlled by a microcomputer.
For a common transistor, the base MUST be fed with sufficient current to
produce saturation. It must be fully-turned-ON and for a motor the
collector current must be about 5 times the operating current.
For a FET transistor the voltage on the gate must be a few volts higher
than the specified gate voltage.
The waveform must be digital. This means it must rise and fall
very quickly. It is called a square wave but the HIGH-time and
LOW-time can be different durations and as these change the output
controls the speed of the motor.
The only time when the transistor will start to get hot is during a slow rise
or fall and that's why the control signal needs to be monitored and
viewed to see its characteristics.
All these things only apply when a high current is being delivered. Small
current don't heat the device.
In addition, when a motor or solenoid is turned off rapidly, it will
produce a back EMF that can be much higher than the supply voltage and
this can destroy the transistor (a transistor gets destroyed much
faster with a spike, than excess current).
These spikes can be removed with a capacitor an-or a diode across the
motor or coil.
It is called SNUBBING or QUENCHING and components are available for high
current - high voltage applications.
Here are the sort of signals that can be processed by a digital stage:

These signals cannot be reproduced accurately by a digital stage:

The rise and fall time is too long and the audio may never turn off the
stage. The FET may get very hot.
When we say the "rise time" is too long, we
mean the time taken for the signal to rise from point A to point B: And
this applies to the full amplitude of the signal.

This is a slow-rise wave

A transistor and FET can be
interchanged (theoretically)

FETs are used for high current
motors
The transistor may not be suitable

The transistor may not be suitable
Transistors are limited
to a gain of about 100 when powering a motor from a microcontroller.
The output current from a micro is 25mA maximum and a 470R resistor will
deliver 20mA to the base of the transistor. This gives a theoretical
2Amp capability to drive a motor. We have already mentioned a motor may
require up to 5 times the running current to get it to start revolving
and so a transistor driver has a number of limitations.
However a FET is voltage-controlled and if the FET will fully turn ON at
5v gate voltage, you can supply any current up to the capability of the
FET. Some FETs will deliver 35 amps or 55 amps. They are also
called MOSFET - Metal Oxide Field Effect Transistor
When doing all your calculations, you need to know the voltage that will
be developed across the Drain-Source junction.
The specification sheet states the junction will develop a
resistance of say 30milliohm for a current up to 3 amps and increase to
70milliohms for 5 amp.
You need to convert this to milliwatts of heat generated by using the
formula Power = I x I x R
When 1 amp is flowing the MOSFET will dissipate 70milliwatts. When
5 amp flows, the dissipation will be 5 x 5 x 0.07 = 1.75 watts.
A transistor will dissipate more than 0.6 x 5 = 3watts when 5 amps
flows.
Any device starts to feel hot when 500milliwatts is dissipated. So both will
need to be heatsinked
There is nothing you can do about these losses. They are called
"characteristics."
Gate voltage may be specified as 2.5v, but if you provide say 4.5v, the
On-resistance will drop 50% for a high current.
Gate voltage can be as high as 12v without any damage.
A MOSFET will operate very similar to an ordinary transistor when the
input voltage is in the "Gate Voltage Range." This may be 0v to
1.5v or 2.5v but this discussion is centered around DIGITAL
APPLICATIONS, where the rise and fall is rapid and the gate voltage will
be 0v to 5v.
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